Teste onde x {\displaystyle x} é:
x ˙ = σ ( y − x ) y ˙ = ρ x − y − x z z ˙ = − β z + x y {\displaystyle {\begin{aligned}{\dot {x}}&=\sigma (y-x)\\{\dot {y}}&=\rho x-y-xz\\{\dot {z}}&=-\beta z+xy\end{aligned}}}
\[ x =y^2 \]
